Darrell Grainger
07-03-2003, 05:01 AM
On 2 Jul 2003, Prof. Mo wrote:
Hi, I'm new to software testing research. It seems to me that it would be pointless to perform white box coverage methods if code inspections and walkthroughs are done. Is this an ideology held by many people in practice?
Pointless is a fairly strong word. I think some people might question the
value of performing both whitebox coverage methods and code inspections.
Each company is different though.
Obviously if I'm creating software that nets me thousands of dollars I'm
going to question whether I want to invest the time and money to do
multiple methods of testing. On the other hand, if I'm making millions and
charging cutomers thousands of dollars a copy then they are going to
expect more and I should take the time to do both operations.
Bottom line, if you can afford to do both, do both.
--
main(){int j=1234;char t[]=":@abcdefghijklmnopqrstuvwxyz.\n",*i=
"iqgbgxmdbjlgdv.lksrqek.n";char *strchr(const char *,int);while(
*i){j+=strchr(t,*i++)-t;j%=sizeof t-1;putchar(t[j]);} return 0;}
Hi, I'm new to software testing research. It seems to me that it would be pointless to perform white box coverage methods if code inspections and walkthroughs are done. Is this an ideology held by many people in practice?
Pointless is a fairly strong word. I think some people might question the
value of performing both whitebox coverage methods and code inspections.
Each company is different though.
Obviously if I'm creating software that nets me thousands of dollars I'm
going to question whether I want to invest the time and money to do
multiple methods of testing. On the other hand, if I'm making millions and
charging cutomers thousands of dollars a copy then they are going to
expect more and I should take the time to do both operations.
Bottom line, if you can afford to do both, do both.
--
main(){int j=1234;char t[]=":@abcdefghijklmnopqrstuvwxyz.\n",*i=
"iqgbgxmdbjlgdv.lksrqek.n";char *strchr(const char *,int);while(
*i){j+=strchr(t,*i++)-t;j%=sizeof t-1;putchar(t[j]);} return 0;}